2016-11-06 18:57发布
求解x（x+2）-5x+10=0，x=多少
x（x+2）-5x+10=0
x²+2x-5x+10=0
x²-3x+10=0
x1=(3+√31)/2
x2=(3-√31)/2
（X+2) - 5X + 10=0
X + 2 - 5X + 10 = 0
5X - X = 12
4X = 12
X = 12 ÷ 4
X = 3
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x（x+2）-5x+10=0
x²+2x-5x+10=0
x²-3x+10=0
x1=(3+√31)/2
x2=(3-√31)/2
（X+2) - 5X + 10=0
X + 2 - 5X + 10 = 0
5X - X = 12
4X = 12
X = 12 ÷ 4
X = 3
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