如上图,红线框起来的部分,为什么字符数组的输入放到里面出来的结果是不正确的,而按照下面的方法,放到循环的外面去输入运行结果是正确的?
正确放法图
下面放完整代码:
#include<iostream> #include<stdio.h> using namespace std; int main(){ char n[100] = { 0 }; int sum = 0; cin>>n; int i, number, mask = 1; for (i = 0; n[i] != 0; i++) { sum += (int)n[i] - 48; } int a = sum; while (a>9){ a /= 10; mask *= 10; } do{ number = sum / mask; sum %= mask; mask /= 10; switch (number){ case 0:printf("ling"); break; case 1:printf("yi"); break; case 2:printf("er"); break; case 3:printf("san"); break; case 4:printf("si"); break; case 5:printf("wu"); break; case 6:printf("liu"); break; case 7:printf("qi"); break; case 8:printf("ba"); break; case 9:printf("jiu"); break; } if (mask>0){ printf(" "); } } while (mask>0); system("pause"); return 0; } 这个题的题目 ![图片描述][3]
我的错误的代码:
#include<iostream> #include<stdio.h> using namespace std; int main(){ char n[100] = { 0 }; int sum = 0, number, mask = 1; for (int i = 0; i != 0; i++){ cin >> n[i]; sum = sum + (int)n[i] - 48; } int a = sum; while (a > 9){ a = a / 10; mask = mask * 10; } do{ number = sum / mask; sum = sum % mask; mask = mask / 10; switch (number){ case 0:printf("ling"); break; case 1:printf("yi"); break; case 2:printf("er"); break; case 3:printf("san"); break; case 4:printf("si"); break; case 5:printf("wu"); break; case 6:printf("liu"); break; case 7:printf("qi"); break; case 8:printf("ba"); break; case 9:printf("jiu"); break; default:break; if (mask > 0){ printf(" "); } } } while (mask > 0); system("pause"); return 0; }
为什么字符数组的输入不放到循环里面呢?而且放到里面的运行结果是错误的。
正如楼上的,这是无限循环啊!
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