a=[                 {                     "user_id":"22b11db4-e907-4f1f-8835-b9daab6e1f23",                     "object_ids":[                         "af86fa9e-65df-47f6-9c35-c3cd17ed8869",                         "39d159e4-1685-bfb3-3c8a-d82da3169e81"                     ]                             },                 {                     "user_id":"39d155ed-da85-7cd5-eda0-1691e2515c6b",                     "object_ids":[                         "af86fa9e-65df-47f6-9c35-c3cd17ed8869",                         "39d159e4-1685-bfb3-3c8a-d82da3169e81",                         "39d1512b-0959-ea02-7a83-2d2cece8fe7d"                     ]                 }             ],              b=["39d159e4-1685-bfb3-3c8a-d82abc69e81", "39d159e4-1685-bfb3-3c8a-d82da3169e99"] 

大概是这样的两个字符串数组，检测b内元素（不会有重复元素）是否在a的object_ids里，每一个object_ids都要检查，object_ids内没有这个元素则a添加这个元素，a内有b内没有则a删除这个元素，难道要分别循环a,b？有什么好思路吗